Question:medium

A block of mass $\sqrt{2}$ kg is placed on a rough horizontal surface. A force 'F' acting upwards at an angle of 45$^\circ$ with the horizontal causes the block to start motion. If the coefficient of static friction between the surface and the block is 0.25, the magnitude of the force 'F' is (Acceleration due to gravity = 10 ms$^{-2}$)

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When a force is applied at an angle to a body on a horizontal surface, it affects both the driving force (horizontal component) and the normal force (vertical component). An upward component of the force reduces the normal force and hence reduces the maximum possible friction.

Updated On: Mar 30, 2026

0.5 N
2 N
4 N
8 N

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The Correct Option is C

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