Question:medium

A block of mass \(5\ \text{kg}\) is on a frictionless surface; find its acceleration when a force of \(10\ \text{N}\) is applied.

Show Hint

On a frictionless surface, acceleration can be directly found using \(a = \frac{F}{m}\) since no opposing force acts on the object.
Updated On: Apr 16, 2026
  • \(1\ \text{m/s}^2\)
  • \(2\ \text{m/s}^2\)
  • \(5\ \text{m/s}^2\)
  • \(10\ \text{m/s}^2\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Question:
We need to calculate the acceleration of a block with a given mass, which is subjected to a known force on a surface without friction.
Step 2: Key Formula or Approach:
The relationship between force, mass, and acceleration is described by Newton's Second Law of Motion. The formula is:
\[ F_{net} = ma \] where \(F_{net}\) is the net force acting on the object, \(m\) is its mass, and \(a\) is its acceleration.
Step 3: Detailed Explanation:
First, identify the given quantities:
- Applied force, \(F = 10 \text{ N}\).
- Mass of the block, \(m = 5 \text{ kg}\).
The problem states that the surface is "frictionless". This is a key piece of information, as it means the applied force is the only horizontal force, and thus it is the net force. So, \(F_{net} = 10 \text{ N}\).
We rearrange Newton's Second Law to solve for acceleration (\(a\)):
\[ a = \frac{F_{net}}{m} \] Substitute the given values into the equation:
\[ a = \frac{10 \text{ N}}{5 \text{ kg}} \] Calculate the result:
\[ a = 2 \text{ m/s}^2 \] (Note: The unit N is equivalent to kg·m/s², so the units are consistent).
Step 4: Final Answer:
The acceleration of the block is \(2 \text{ m/s}^2\).
Was this answer helpful?
0