Question:medium

A block of mass \(2\, \text{kg}\) is placed on a smooth horizontal surface. A force of \(10\, \text{N}\) is applied horizontally on the block. What is the acceleration of the block?

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When the surface is smooth (frictionless), you can directly apply \( F = ma \) without accounting for frictional forces.
Updated On: Nov 26, 2025
  • \(2.5 \, \text{m/s}^2\)
  • \(5 \, \text{m/s}^2\)
  • \(10 \, \text{m/s}^2\)
  • \(20 \, \text{m/s}^2\)
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The Correct Option is B

Solution and Explanation

Given: - Mass of the block (\(m = 2\, \text{kg}\)) - Applied force (\(F = 10\, \text{N}\)) - Frictionless surface. Step 1: Apply Newton’s Second Law Newton’s Second Law states: \[ F = m \cdot a \] Rearranging to solve for acceleration (\(a\)): \[ a = \frac{F}{m} \] Substituting the given values: \[ a = \frac{10}{2} = 5 \, \text{m/s}^2 \] Step 2: Conclusion The acceleration of the block is \(5 \, \text{m/s}^2\). Answer: The acceleration is \(5 \, \text{m/s}^2\).
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