A binary signal is transmitted at 10kbps using NRZ signaling. Find the minimum channel bandwidth required in KHz:

Question

The percentage of the total power carried by the sidebands of the AM wave for tone modulation when the modulation index is 0.3 is:

Answer 1

Understanding the Concept: In baseband digital communication using Non-Return-to-Zero (NRZ) line coding:
• The minimum bandwidth required to transmit a signal without Inter-Symbol Interference (ISI) is defined by the Nyquist criterion.
• For a bit rate of \( R_b \), the absolute minimum theoretical bandwidth (Nyquist bandwidth) required is: \[ B_{\min} = \frac{R_b}{2} \]

Step 1: Substitute Given Values into Formula
The given transmission rate is: \[ R_b = 10\,\text{kbps} \] Applying the minimum bandwidth formula: \[ B_{\min} = \frac{10\,\text{kbps}}{2} = 5\,\text{kHz} \] Thus, the minimum channel bandwidth required is exactly 5 kHz, corresponding directly to Option (B).

List-I (Modulation Schemes)	List-II (Wave Expressions)
(A) Amplitude Modulation	(I) \( x(t) = A\cos(\omega_c t + k m(t)) \)
(B) Phase Modulation	(II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \)
(C) Frequency Modulation	(III) \( x(t) = A + m(t)\cos(\omega_c t) \)
(D) DSB-SC Modulation	(IV) \( x(t) = m(t)\cos(\omega_c t) \)

A binary signal is transmitted at 10kbps using NRZ signaling. Find the minimum channel bandwidth required in KHz:

Show Hint

The Correct Option is B

Solution and Explanation

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