Question:medium

A balloon, which always remains spherical, has a variable radius. The rate at which its volume is increasing with respect to its radius $r$ when $r = 5$ cm is:

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Differentiating volume with respect to radius always yields the surface area of the sphere: $\frac{dV}{dr} = 4\pi r^2$. Simply plug in the radius to get the area directly!

Updated On: May 31, 2026

$100\pi$
$50\pi$
$25\pi$
$10\pi$

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The Correct Option is A

Solution and Explanation

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A balloon, which always remains spherical, has a variable radius. The rate at which its volume is increasing with respect to its radius $r$ when $r = 5$ cm is:

Show Hint

The Correct Option is A

Solution and Explanation

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