Step 1: Employ the equation of motion for velocity
The velocity of an object in free fall from a specific height is determined by:\[v^2 = u^2 + 2gh\]With the following variables:- \( v \) representing the final velocity,
- \( u \) denoting the initial velocity (zero for free fall),
- \( g \) indicating the acceleration due to gravity,
- \( h \) specifying the drop height.
Step 2: Insert the provided values Provided data:- Initial velocity \( u = 0 \, \text{m/s} \),
- \( g = 9.8 \, \text{m/s}^2 \),
- Height \( h = 20 \, \text{m} \).
Substituting these into the equation yields:\[v^2 = 0 + 2 \times 9.8 \times 20 = 392\]\[v = \sqrt{392} \approx 14 \, \text{m/s}\]Answer: The ball's velocity upon impact with the ground is approximately \( 14 \, \text{m/s} \). This corresponds to option (2).