Question

A bag contains \(3\) white, \(2\) blue and \(5\) red balls. One ball is drawn at random from this bag. Then, the probability that the ball drawn is not red is

• A. \(\frac{3}{10}\)
• B. \(\frac{1}{5}\)
• C. \(\frac{1}{2}\)
• D. \(\frac{4}{5}\)

Hint:

For simple probability problems, first count the favorable outcomes and total outcomes, then use \[ P(E)=\frac{\text{Favorable outcomes}}{\text{Total outcomes}}. \]

Answer 1

The Correct Option is C

Step 1: Count non-red balls.
Total = \(3+2+5=10\). Non-red = \(3+2=5\).

Step 2: Compute probability.
\[P(\text{not red}) = \frac{5}{10} = \frac{1}{2}.\]
\[\boxed{\frac{1}{2}}\]