To solve this problem, we need to understand the ozonolysis reaction applied to the given compounds and how it leads to the formation of the specified products.
A \xrightarrow[(2)Zn-H_2O]{(1)O_3} Ethane-1, 2-dicarbaldehyde + Glyoxal
Ozonolysis of A leading to the formation of ethane-1, 2-dicarbaldehyde (glyoxal or oxaldehyde) indicates that A must have a structure that breaks into two aldehyde groups.
The only diene option in the list that would break into simple aldehydes upon ozonolysis is Cyclohex-1, 3-diene. Ozonolysis of this compound results in two smaller aldehyde molecules: ethane-1, 2-dicarbaldehyde and another aldehyde or ketone depending on the substituents.
B \xrightarrow[(2)Zn-H_2O]{(1)O_3} 5 - oxohexanal
Ozonolysis of B yielding 5-oxohexanal suggests that the compound has a structure that can be cleaved to form a six-carbon chain with a ketone and an aldehyde group.
For 1-methylcyclopent-1-ene, ozonolysis can lead to a linear compound containing an aldehyde and ketone, matching the product 5-oxohexanal. The presence of the methyl group shifts such a cleavage.
After analyzing both reactions, we can conclude:
A = Cyclohex-1, 3-diene
B = 1-methylcyclopent-1-ene
Therefore, the correct answer is Cyclohex-1, 3-diene \;&\; 1-methylcyclopent-1-ene.
