Mass of engine, \( m_e = 8000 \, \text{kg} \)
Mass of each wagon, \( m_w = 2000 \, \text{kg} \), number of wagons = 5
Force exerted by engine, \( F_{\text{engine}} = 40000 \, \text{N} \)
Friction force, \( F_{\text{friction}} = 5000 \, \text{N} \)
\[ m_{\text{total}} = m_e + 5 \cdot m_w = 8000 + 5 \cdot 2000 = 18000 \, \text{kg} \]
\[ F_{\text{net}} = F_{\text{engine}} - F_{\text{friction}} \] \[ F_{\text{net}} = 40000 - 5000 = 35000 \, \text{N} \]
Using Newton's second law: \[ a = \frac{F_{\text{net}}}{m_{\text{total}}} = \frac{35000}{18000} \approx 1.94 \, \text{m/s²} \]
(a) Net accelerating force = 35000 N
(b) Acceleration of the train = 1.94 m/s²