A $ 500 \,kg $ car takes a round turn of radius $ 50\, m $ with a velocity of $ 36\, km/h $ . The centripetal force is

Question

A ball is thrown vertically upwards with an initial velocity of $ 20 \, \text{m/s} $. How high will the ball rise? (Take $ g = 10 \, \text{m/s}^2 $)

Answer 1

To find the centripetal force acting on a car that is making a round turn, we can use the formula for centripetal force:

F = \frac{mv^2}{r}

where:

F is the centripetal force,
m = 500 \, \text{kg} is the mass of the car,
v is the velocity of the car,
r = 50 \, \text{m} is the radius of the turn.

First, we need to convert the velocity from km/h to m/s:

v = 36 \, \text{km/h} = \frac{36 \times 1000 \, \text{m}}{3600 \, \text{s}} = 10 \, \text{m/s}

Now, we substitute the values into the centripetal force formula:

F = \frac{500 \times (10)^2}{50}

Simplifying this, we get:

F = \frac{500 \times 100}{50} = \frac{50000}{50} = 1000 \, \text{N}

Thus, the centripetal force acting on the car is 1000 \, \text{N}.

Therefore, the correct answer is 1000 \, \text{N}.

Answer 2