Question

58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point of the resulting solution.

• A. NaCl solution will show higher elevation of boiling point.
• B. Glucose solution will show higher elevation of boiling point.
• C. Both solutions will show equal elevation of boiling point.
• D. None will show boiling point elevation.

Hint:

Ionic compounds like NaCl dissociate in water, increasing the effect on colligative properties.

Answer 1

The Correct Option is A

Step 1: Molar Calculation of Solute
\[{Moles of NaCl} = \frac{58.5}{58.5} = 1 { mol}\]\[{Moles of Glucose} = \frac{180}{180} = 1 { mol}\]Step 2: NaCl Dissociation Analysis
NaCl dissociates into \( Na^+ \) and \( Cl^- \) ions, leading to a higher effective particle concentration. Glucose remains undissociated, maintaining its particle count. Consequently, the NaCl solution will exhibit a greater boiling point elevation. Therefore, the correct option is (A).