Raoult's law predicts the vapor pressure of an ideal solution using the formula: \[ P_{\text{solution}} = X_X P_X^0 + X_Y P_Y^0 \]. In this equation, \( P_{\text{solution}} \) represents the solution's vapor pressure, \( X_X \) and \( X_Y \) are the mole fractions of components X and Y, and \( P_X^0 \) and \( P_Y^0 \) are the vapor pressures of pure X and Y, respectively. Given Moles of X = 5, Moles of Y = 10, \( P_X^0 = 63 \, \text{torr} \), and \( P_Y^0 = 78 \, \text{torr} \). The total moles are 5 + 10 = 15. The mole fractions are calculated as: \[ X_X = \frac{5}{15} = \frac{1}{3}, \quad X_Y = \frac{10}{15} = \frac{2}{3} \]. Applying Raoult's law yields: \[ P_{\text{solution}} = \left(\frac{1}{3}\right)(63) + \left(\frac{2}{3}\right)(78) \] \[ P_{\text{solution}} = 21 + 52 = 73 \, \text{torr} \]. The provided vapor pressure is 70 torr, which is less than the calculated 73 torr. This indicates negative deviation from Raoult's law. Consequently, the solution exhibits negative deviation. Therefore, the correct answer is (1) The solution shows negative deviation.
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