Question:medium
પરમાણુ પ્રતિક્રિયા \( ^{238}\text{U} \to ^{234}\text{Th} + ^4\text{He} \) ને ધ્યાનમાં લો. દ્રવ્યમાન: 238.050 u, 234.043 u, 4.003 u. પ્રતિક્રિયાનું Q-મૂલ્ય (keVમાં) છે:
પરમાણુ પ્રતિક્રિયા \( ^{238}\text{U} \to ^{234}\text{Th} + ^4\text{He} \) ને ધ્યાનમાં લો. દ્રવ્યમાન: 238.050 u, 234.043 u, 4.003 u. પ્રતિક્રિયાનું Q-મૂલ્ય (keVમાં) છે:
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1 MeV = 1000 keV. હંમેશા એકમોનું કાળજીપૂર્વક રૂપાંતરણ કરવું!
Updated On: Jun 23, 2026
- 3740
- 3726
- 3730
- 3736
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Q-value formula.
\( Q = \Delta m \times 931.5 \) MeV.
Step 2: Mass defect.
\( \Delta m = 238.050 - (234.043 + 4.003) = 0.004 \) u.
Step 3: Final.
\[ Q = 0.004 \times 931.5 = 3.726 \text{ MeV} = 3726 \text{ keV} \] \[ \boxed{3726 \text{ keV}} \]
\( Q = \Delta m \times 931.5 \) MeV.
Step 2: Mass defect.
\( \Delta m = 238.050 - (234.043 + 4.003) = 0.004 \) u.
Step 3: Final.
\[ Q = 0.004 \times 931.5 = 3.726 \text{ MeV} = 3726 \text{ keV} \] \[ \boxed{3726 \text{ keV}} \]
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