2 pipes can fill a tank in 10 minutes together. If the efficiency of the first pipe is 8 times the efficiency of the second pipe, find the time required to fill the tank using the second pipe alone.
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When efficiency is given as a multiple "n", the time for the slower pipe alone is always \(\text{Together Time} \times (n + 1)\). Here: \(10 \times (8 + 1) = 90\).