Step 1: Fix one player:
Seat the captain first. Relative to him the keeper can sit in $10$ other seats, but $2$ of them are adjacent to the captain, so $8$ seats are allowed.
Step 2: Seat the rest:
The other $9$ players fill the remaining $9$ seats in $9!$ ways.
Total $= 8 \times 9!$.
Final Answer:
The count is $8 \times 9!$, option (C).
\[ \boxed{8 \times 9!} \]