10 W is to be delivered to a device via a wire having resistance \(2\,\Omega\). If 20 V is the voltage across the device, the power wasted in the process is:
Show Hint
Use \(P_{loss} = I^2R\) when current is known; use \(VI\) only when voltage drop is required.
Step 1: Device current. P = VI → 10 = 20 × I → I = 0.5 A. Step 2: Voltage drop across wire. V_loss = IR = 0.5 × 2 = 1 V. Step 3: Power dissipated in wire. P_loss = I²R = (0.5)² × 2. Step 4: Numerical evaluation. P_loss = 0.25 × 2 = 0.5 W. Step 5: Physical origin. This waste is Joule heating in the connecting leads. Step 6: Conclusion. The wasted power is 0.5 W.