Question:medium
0.5 g of an organic compound on combustion gave 1.46 g of $ CO_2 $ and 0.9 g of $ H_2O $. The percentage of carbon in the compound is ______ (Nearest integer) $\text{(Given : Molar mass (in g mol}^{-1}\text{ C : 12, H : 1, O : 16})$
0.5 g of an organic compound on combustion gave 1.46 g of $ CO_2 $ and 0.9 g of $ H_2O $. The percentage of carbon in the compound is ______ (Nearest integer) $\text{(Given : Molar mass (in g mol}^{-1}\text{ C : 12, H : 1, O : 16})$
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During combustion of an organic compound, all the carbon present in the compound is converted to \( CO_2 \). Use the molar mass ratio to find the mass of carbon in the \( CO_2 \) produced and then calculate the percentage of carbon in the organic compound.
Updated On: Jan 14, 2026
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Correct Answer: 80
Solution and Explanation
Organic Compound yields CO2.
POAC (Proportionality Of Atomic Composition) is applied to 'C'.
Moles of 'C' in the compound = moles of CO2 × 1.
Mass of 'C' in the compound = $\dfrac{1.46}{44} \times 12$.
Therefore, the percentage of 'C' in the compound =
\[ \dfrac{1.46}{44} \times \dfrac{12}{0.5} \times 100 \]= 79.63%.
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