List of top Physics Questions on Combination of capacitors asked in MET

In the following circuit diagram, potential difference across \(4\mu F\) capacitor is:

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Two capacitors of capacitance \(2\mu F\) and \(6\mu F\) are connected in series. A potential difference of 800 V is applied to the outer plates of the two capacitors system. The charge on each capacitor will be :

Five equal capacitors each with capacitance \(C\) are connected as shown in the figure. Then, the equivalent capacitance between \(A\) and \(B\) is:

If the length of a pendulum is made 9 times and mass of bob is made 4 times, then the value of time period becomes

A 10 \(\mu\)F capacitor is charged to a potential difference of 50 V and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes 20 V. The capacitance of second capacitor is:

Two parallel plates of area A are separated by two different dielectrics as shown in figure. The net capacitance is