List of top Chemistry Questions on Photoelectric Effect asked in MET

If the frequency of incident photon on a metal surface is doubled, then stopping potential will become:

Which of the following conclusion is correct regarding photoelectric effect?

Light of wavelength \(2475\,\text{\AA}\) is incident on barium. Photoelectrons emitted describe a circle of radius \(100\,\text{cm}\) in a magnetic field of flux density \(\frac{1}{\sqrt{17}} \times 10^{-5}\) tesla. The value of work function of barium is _ _ _ _ _ eV. (Given \(e/m = 1.7 \times 10^{11}\))

The electric field of light wave is given as \[ E = 10^3 \cos \left( \frac{2\pi x}{5 \times 10^{-7}} - 2\pi \times 6 \times 10^{14} t \right)\hat{j} \, \mathrm{N/C} \] This light falls on a metal plate of work function \( 1.5\, \mathrm{eV} \). The stopping potential of the photoelectron is \( \_\_\_ \, \mathrm{V} \).
(Energy of photon = \( \frac{1240}{\lambda \, (\text{in nm})} \, \mathrm{eV} \))

If \( \lambda \) is the incident wavelength and \( \lambda_0 \) is the threshold wavelength for a metal surface, photoelectric effect takes place only if:

The maximum kinetic energy of photoelectrons coming out of a metal surface is \(10 \, \text{eV}\). The minimum voltage required to stop the emission of electrons from this metal surface is:

Which of the following elements has maximum photoelectric effect?

In photoelectric effect, if wavelength changes from \(\lambda\) to \(3\lambda/4\), how does max speed change?

Minimum intensity of light detectable is \(10^{-10}\,W/m^2\). Number of photons entering eye per second (\(\lambda=5.6\times10^{-7}m\), pupil area \(10^{-6}m^2\)).

The oxide of an element whose electronic configuration is $1s^{2}, 2s^{2}, 2p^{6}, 3s^{1}$ is

Light of wavelength 5000 falls on a sensitive plate with photoelectric work function 1.9 eV. The kinetic energy of the photoelectron is: