List of top Physics Questions on Kinematics asked in KEAM

The magnitude and direction of acceleration change in the case of an object

The displacement of a body at any time t is given by \[ x = -\frac{3}{4}t^2 + 12t + 3 \] The velocity of the body is zero after:

When a body is thrown vertically upwards, from the ground, the time of ascent is \( t_1 \) and the time of descent is \( t_2 \) in the absence of air resistance. Then \( t_1 \) is equal to

Two objects, P and Q, travelling in the same direction starts from rest. While the object P starts at time $t=0$ and the object Q starts later at $t=30$ min. The object P has an acceleration of $40 \text{ km/h}^2$. To catch P at a distance of $20$ km, the acceleration of Q should be}

A particle starting with certain initial velocity and uniform acceleration covers a distance of 12 m in first 3 seconds and a distance of 30 m in next 3 seconds. The initial velocity of the particle is

A particle starting with certain initial velocity and uniform acceleration covers a distance of 12 m in first 3 seconds and a distance of 30 m in next 3 seconds. The initial velocity of the particle is

A particle starting with certain initial velocity and uniform acceleration covers a distance of 12 m in first 3 seconds and a distance of 30 m in next 3 seconds. The initial velocity of the particle is