The oxidation of ferrous oxalate by \(KMnO_4\) in acidic medium is given by the following equation, \(3MnO_4^- + 5FeC_2O_4 + 24H^+ \to 3Mn^{2+} + 5Fe^{3+} + 10CO_2 + 12H_2O\). What is the volume of \(0.01 \text{ mol dm}^{-3}\) \(KMnO_4\) required to oxidise \(15 \text{ cm}^3\) of an acidified solution of \(0.01 \text{ mol dm}^{-3}\) ferrous oxalate?