List of practice Questions

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of the ring, is \((\frac{1}{x})MR^2\), where R is the radius and M is the mass of the semicircular ring. The value of x will be:

Two blocks $A$ and $B$ of masses $m_A = 1 \; kg$ and $m_B = 3 \; kg$ are kept on the table as shown in figure. The coefficient of friction between $A$ and $B$ is $0.2$ and between $B$ and the surface of the table is also $0.2.$ The maximum force $F$ that can be applied on $B$ horizontally, so that the block $A$ does not slide over the block $B$ is : (Take $g = 10 \; m/s^2$)