List of top Chemistry Questions on Equilibrium Constant asked in JEE Main

37.8 g $ N_2O_5 $ was taken in a 1 L reaction vessel and allowed to undergo the following reaction at 500 K: \[ 2N_2O_5(g) \rightarrow 2N_2O_4(g) + O_2(g) \]
The total pressure at equilibrium was found to be 18.65 bar. Then, $ K_p $ is: Given: \[ R = 0.082 \, \text{bar L mol}^{-1} \, \text{K}^{-1} \]

At $298\ K$
$N_2( g)+3H_2( g)⇌2NH_3( g),K_1=4×10^5$
$N_2( g)+O_2( g)⇌2NO(g),K_2=1.6×10^{12}$
$H_2( g)+1 2O_2( g)⇌H_2O(g),K_3=1.0×10^{−13}$
Based on above equilibria, the equilibrium constant of the reaction,
$2NH_3( g)$+$\frac5 {2}$ $O_2( g)⇌2NO(g)+3H_2O(g)$ is _______ $×10^{−33 }$. (Nearest integer)

The equilibrium constant for the reaction
$Zn(s)+Sn^{2+}(aq)⇌Zn^{2+}(aq)+Sn(s)\, is\, 1×10^{20}$ at $298 K$.
The magnitude of standard electrode potential of $Sn/Sn^{2+}$ if $E^{\degree}_{ Zn^{2+}/Zn}= –0.76V $ is _______ $×10^{−2} V$. (Nearest integer).
(Given : $\frac{2.303RT}{ F}$ $=0.059 V $)

$PCl_5$ dissociates as
$PCl_5(g) ⇌ PCl_3(g)+ Cl_2(g)$
$5$ moles of $PCl_5$ are placed in a $200$ litre vessel which contains $2$ moles of $N_2$ and is maintained at $600\ K$. The equilibrium pressure is $2.46$ atm. The equilibrium constant Kp for the dissociation of $PCl_5$ is ______ $× 10^{–3}$. (nearest integer)
(Given: $R = 0.082$ L atm K^–1 mol^–1; Assume ideal gas behaviour)

At $298\ K$, the equilibrium constant is $2 × 10^{15}$ for the reaction:
$Cu(s)+2Ag+(Aq)⇌Cu^{2+}(aq)+2Ag(s)$
The equilibrium constant for the reaction:
$\frac 12Cu^{2+}(aq)+Ag(s)+(Aq)⇌\frac 12Cu(s)+Ag^+(aq)$ is $x \times10^{-8}$.
The value of $x$ is ______ . (Nearest integer)

If the standard electrode potential for a cell is 2 V at 300 K, the equilibrium constant (K) for the reaction ${Zn(s) + cu^{2+} (aq) <=> Zn^{2+} (aq) + Cu(s)}$ at 300 K is approximately. ${(R = 8 \; JK^{-1} \; mol^{-1} , F = 96000 \; C \; mol^{-1})}$