List of top Chemistry Questions on Surface Tension asked in BITSAT

A mercury drop of radius 1 cm is sprayed into 10⁶ drops of equal size. The energy expressed in joules is (surface tension of mercury is 460 × 10⁻3N/m):
A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is M. If the radius of the tube is doubled, mass of water that will rise in the capillary tube will now be
A capillary tube of radius r is immersed vertically in a liquid such that liquid rises in it to height h (less than the length of the tube). Mass of liquid in the capillary tube is m. If radius of the capillary tube is increased by 50%, the mass of liquid that will rise in the tube is:
A glass capillary tube of internal radius r = 0.25mm is immersed in water. The top end of the tube is projected by 2cm above the surface of the water. At what angle does the liquid meet the tube? Surface tension of water = 0.7N/m.
A mercury drop of radius 1 cm is sprayed into \(10^6\) drops of equal size. The energy expressed in joules is (surface tension of mercury is \(460 \times 10^{-3} \, \text{N/m}\)).
A capillary tube of radius R is immersed in water and water rises in it to a height H. Mass of water in the capillary tube is M. If the radius of the tube is doubled, mass of water that will rise in the capillary tube will now be
A capillary tube of radius r is immersed vertically in a liquid such that liquid rises in it to height h (less than the length of the tube). Mass of liquid in the capillary tube is m. If radius of the capillary tube is increased by 50%, then mass of liquid that will rise in the tube is:
A glass capillary tube of internal radius \(r = 0.25\,\text{mm}\) is immersed in water. The top end of the tube is projected by \(2\,\text{cm}\) above the surface of the water. At what angle does the liquid meet the tube? (Surface tension of water \(=0.7\,\text{N/m}\)).
The work done in blowing a soap bubble of surface tension \(0.06 \text{ N m}^{-1}\) from radius \(2 \text{ cm}\) to \(5 \text{ cm}\) is:
Two mercury drops (each of radius r) merge to form a bigger drop. The surface energy of the bigger drop, if the surface tension is T, is
Two circular plates of radius 5 cm each have a 0.01 mm thick water film between them. What will be the force required to separate these plates? (Surface tension of water = 73 dyne/cm)