List of top Mathematics Questions on Combinations asked in AP EAPCET

If $^{n}C_{12} = ^{n}C_{8}$, then $^{n}C_{17} =$

Let \(T_n\) be the number of all possible triangles formed by joining vertices of an \(n\)-sided regular polygon. If \[ T_{n+1}-T_n=10, \] then the value of \(n\) is

Given \(5\) different green toys, \(4\) different blue toys, and \(3\) different red toys, how many combinations of toys can be chosen taking at least one green and one blue toy?

If \[ {}^{2n}C_3 : {}^{n}C_3 = 12:1, \] then \(n=\)

There are \(4\) oranges, \(5\) apples, \(7\) mangoes in a fruit basket. The number of ways of selecting at least one fruit from among the fruits in the basket is

If \[ {}^{9}C_3+{}^{9}C_5={}^{10}C_r \] for some \(r\in \mathbb{N}\), then \(r=\)

If \[ {}^{10}C_2=3\cdot {}^{n+1}C_3, \] then the value of \(n\) is

There are \(10\) points in a plane, out of these \(6\) are collinear. If \(N\) is the total number of triangles formed by joining these points, then \[ N= \]

In an examination, the maximum marks for each of three subjects is \(n\) and that for the fourth subject is \(2n\). The number of ways in which candidates can get \(3n\) marks is

The least value of \(n\) so that \[ {}^{\,n-1}C_3+{}^{\,n-1}C_4\gt {}^{\,n}C_3 \] is

A student is to answer \(10\) out of \(13\) questions in an examination such that he must choose at least \(4\) from the first \(5\) questions. The number of choices available to him is: