Resistance of a conductivity cell filled with \(0.1 \text{ mol L}^{-1}\) NaCl is \(100 \, \Omega\). If the resistance of the same cell when filled with \(0.02 \text{ mol L}^{-1}\) NaCl solution is \(258 \, \Omega\), then the conductivity of \(0.02 \text{ mol L}^{-1}\) NaCl solution is:
\[
\text{(Conductivity of }0.1 \text{ mol L}^{-1}\text{ NaCl} = 1.29 \, \text{S m}^{-1})
\]